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kati45 [8]
3 years ago
10

A number greater than a thousand whos prime factorization contains one prime number that does not repeat, one prime number that

repeats 3 times,and one prime number that repeats twice
Mathematics
1 answer:
Nikitich [7]3 years ago
8 0

You can build as many numbers as you like: just pick three primes and repeat them as required.

The only caution is that you have to pick large enough primes to make sure that the result is larger than 1000.

Since 10^3 = 1000, it is enough that the prime repeating three times is larger than 10.

So, for example, we can pick

  • 2, not repeating
  • 3, repeating twice
  • 11, repeating 3 times

The result is

2 \times 3^2 \times 11^3 = 23958

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During his summer vacation, Alex spent 6 minutes riding his bike for every minute he spent watching television. If he rode his b
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Solve the equation 7/z-1 = 9/z+4
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z is equal to 18.5

Step-by-step explanation:

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3 0
2 years ago
Given a term and the common difference, find the explicit formula.<br> 8. a(19) = 135<br> d = 15
Rasek [7]

The explicit formula is a(n) = 15(n – 10)

<u>Solution:</u>

Given, a term a(19) = 135 and common difference d = 15

We have to find the explicit formula.

Now, we know that, a(n) = a + (n – 1)d where a(n) is nth term, a is first term, d is common difference,

So, for a(19)  

\begin{array}{l}{\rightarrow a(19)=a+(19-1) 15} \\\\ {\rightarrow 135=a+18 \times 15} \\\\ {\rightarrow a=135-270} \\\\ {\rightarrow a=-135}\end{array}

Now, we know that, an explicit formula is an expression for finding the nth term,  

So, in our problem, expression for finding nth term is a + (n – 1)d  

\begin{array}{l}{\rightarrow-135+(n-1) 15} \\\\ {\rightarrow-135+15 n-15} \\\\ {\rightarrow 15 n-150} \\\\ {\rightarrow 15(n-10)}\end{array}

Hence, the explicit formula is a(n) = 15(n – 10).

7 0
3 years ago
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