<h3>Given</h3>
Two positive integers x and y
x - y = 4
x² + y = 68
<h3>Find</h3>
x and y
<h3>Solution</h3>
Add the two equations together.
... (x - y) + (x² + y) = (4) + (68)
... x² + x = 72
Rearrange to standard form and factor.
... x² + x - 72 = 0
... (x + 9)(x - 8) = 0
Use the zero product rule to find the solutions. That rule says the product is zero when one or more factors is zero.
... x + 9 = 0 ⇒ x = -9
... x - 8 = 0 ⇒ x = 8 . . . . . . the positive solution
Then we can find y from
... 8 - y = 4
... y = 4 . . . . . . . add y-4 to the equation
The two positive integers are 8 and 4.
The answer is -20 I hope this helped
3. 20-(5x2). The answer is 10. [20-(5x2) -> 20-10=10]
4. B (Parenthesis are needed) and C (Start with simplifying the bottom).
5. 6x(9-3). The answer is 36. [6x(9-3) -> 6x6=36]
6. 10 divided by the difference of 6 and 4.
7. B
8. (5+7)x3 -> 12x3=36
Sorry not to sure about this answer and don’t want to get it wrong sorry
Answer:
Exact form:221/20
Decimal form:11.05
Mixed Number form:11 1/20
Step-by-step explanation:
