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sergeinik [125]

2 years ago

5

Need help PLZZZZZZZZZZZZZ

2 answers:

Dmitry [639]2 years ago

8 0

3/4*2*8
3/4*16
(3*16)/4
48/4
12
So the answer is C.

Hope this helps :)

loris [4]2 years ago

3 0

(c) he spent 12 hours

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What is a - 5 - 6a + 3

Yakvenalex [24]

Answer:

-7-5a

Step-by-step

i simplified it if thats what it meant

4 0

2 years ago

A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and

goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

$\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}$

Solve for S(t):

$\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}$

$e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}$

The left side is the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}$

Integrate both sides:

$e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt$

$e^{t/800}S(t)=64e^{t/800}+C$

$S(t)=64+Ce^{-t/800}$

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

$0=64+C\impleis C=-64$

and so (b) the amount of sugar in the tank at time t is

$S(t)=64\left(1-e^{-t/800}\right)$

As $t\to\infty$ , the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

7 0

3 years ago

Identify the sine function with the given attributes.

Thepotemich [5.8K]

Answer:

<em>Last option </em>

$f(t)=sin(\pi(t -3)) + 4$

Step-by-step explanation:

The general sine function has the following form

$y = Asin(bt-\phi) + k$

Where A is the amplitude: half the vertical distance between the highest peak and the lowest peak of the wave.

$\frac{2\pi}{b}$ is the period: time it takes the wave to complete a cycle.

k is the vertical displacement.

$\phi$ phase shift

We know that:

amplitude: 1; period: 2; phase shift: 3; vertical shift: 4

Thus:

$A =1$

$\frac{2\pi}{b}=2$

$b=\pi$

$\phi=3$

$k=4$

Then the function is:

$f(t)=sin(\pi(t -3)) + 4$

The answer is last option

4 0

2 years ago

In a class of 29 students, 19 are female and 14 have an A in the class. There are 8students who are male and do not have an A in

masya89 [10]

SOLUTION

The total number of females =

$19$

if 14 have an A in the class, the number of students without A is:

$29-14=15$

8 male students do not have an A, therefore the number of female students without an A is:

$15-8=7$

The probability that a student does not have an A given that the student is female can be calculated thus:

$\frac{\text{Total number of female students without an A}}{Total\text{ number of female students in the class}}$ $\frac{7}{19}$

8 0

9 months ago

Please help I will mark branliest

Sladkaya [172]

3 because a polygon has 3 or more sides

8 0

2 years ago