Because when we draw a point ,we draw a very very small line....one can see how this might lead to a problem.consider a line that is 1 inch long,what we want to looked at 1/1000 through that line it would still be a line.but,if we drew it ,it would look like a point....
Answer:
C
Step-by-step explanation:
it cant pass since multiple points intersect
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The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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The answer is 7 because 2 to 5 is 3 and -2 to 5 I 7
