Question

Birth weights in Norway are normally distributed with a mean of 3570 g and a standard deviation of 500 g. Find the probability that 100 randomly selected birth weights have a mean between 3500 g and 3600 g.
A) 0.7257
B) 0.3551
C) 0.6449
D) 0.0796

Answer 1

Answer:

D) 0.0796

Step-by-step explanation:

Birth weights in Norway are normally distributed with a mean of 3570 g and a standard deviation of 500 g.

mean = 3570  and SD = 500

We need to find P(3500<x<3600)

P(3500<x<3600)= P(x=3600)- P(x=3500)

to find P(x=3600) we find z-score

$z= \frac{x-mean}{SD} =\frac{3600-3570}{500} =0.06$

Now use z-score table . z-score = 0.5239

P(x=3600)=0.6179

to find P(x=3500) we find z-score

$z= \frac{x-mean}{SD} =\frac{3500-3570}{500} =-0.14$

Now use z-score table . z-score = 0.4443

P(x=3600)=0.4443

P(3500<x<3600)= P(x=3600)- P(x=3500)

P(3500<x<3600)=0.5239-0.4443 = 0.0796

Answer 2

Answer:  0.6449

(The one above is wrong)