So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.
First thing to do is to figure out how many additional lessons are in that, which are 5.
Then you can make a 1 variable equation with the information you have. I’m using x as my variable.
260= 3/2x + 5x
Combine like terms.
260 = 13/2x
Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)
X=40
Answer:
"A" IS THE ANSWER
Step-by-step explanation:
Answer:
−30a−6
Step-by-step explanation:
Let's simplify step-by-step.
−9a−10−6a+7−9a−10−6a+7
=−9a+−10+−6a+7+−9a+−10+−6a+7
Combine Like Terms:
=−9a+−10+−6a+7+−9a+−10+−6a+7
=(−9a+−6a+−9a+−6a)+(−10+7+−10+7)
=−30a+−6
BRAINLIEST. if you don't mind.
So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;
2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5
Hope this helps you. Any questions please ask.
Mason needs 9 more seed packets to have a total of 20 plants in his yard.
Simplified:
20-11=9
