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galben [10]
3 years ago
13

Melinda purchased 3 blank cassette tapes and 5 blank videotapes for a total of $22.10 not including tax. if each videotape cost

twice the price of cassette tape, what did Melinda pay for 1 videotape?
Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

The cost of 1 videotape  =  $ 3.4

Step-by-step explanation:

Let us assume the cost of each cassette tap  = $ m

So, the cost of each videotape  = 2 x ( Cost of 1 cassette)  = 2 x  m = 2 m

Now, the cost of 3 cassette tap = 3 x ( Cost of 1 cassette)  = 3  x  m = 3 m

Also, the cost of 5 videotape = 5 x ( Cost of 5 videotape)  = 5  x  (2m) = 10 m

So, the cost of 3 cassette tap + 5 videotape  = 3 m + 10 m

Also, given 3 blank cassette tapes and 5 blank videotapes  costs $22.10 .

⇒ 3 m + 10 m = $22.10

or, 13 m =  22.10

⇒ m = 22.10/13  =1.7

or, m = $1.7

Hence, the cost of 1 cassette = m = $1.7

And, the cost of 1 videotape  = 2 m = 2x ($1.7) =  $ 3.4

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3

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3 years ago
Find (r-s) (t-s) + (s-r) (s-t) for all numbers r, s, and t. (a) 0 (b) 2 (c) 2rt (d) 2(s-r) (t-s) (e) 2(r-s) (t-s)
lyudmila [28]
Notice that the 2 expressions have 2 common terms.

(r-s) is just (s-r) times (-1)

similarly

(t-s) is just (s-t) times (-1)

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the 2 minuses in the first multiplication cancel each other so we have:

-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)

Answer:

d)<span>2(s-r) (t-s) </span>
3 0
3 years ago
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Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A
lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

  • Part A: <u>ΔABC is similar to ΔADC</u>
  • Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>
  • Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

Learn more here:

brainly.com/question/2269451

3 0
2 years ago
What is the distance between 178 and 313 on a number line?
Damm [24]

Answer:

135 is the distance

Step-by-step explanation:

I subtracted the numbers.

I hope this helped and have a great day!

(please vote this brainliest)

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Troyanec [42]
The value of the expression is A.13
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