Answer:
<h3>Sv is angle bisector of rst.</h3>
Answer: x= 3,2
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
The angle does not matter. Think of it as finding the other side to a triangle. Use

a=39 (line AB)
b=b (the leg we need to find)
c=89 (line BD)


(subtract the 1521 from both sides)

(square root both sides)

b = 80
AD=80
Answer:
A. You would first plot the y intercept. The first equation would be (0,-8) and the second equation is (0,-11). Then you would plot the slope. For the first equation, from (0,-8), you would move up 3 plots and right 1 plot. For the second equation, from (0,-11), you would move up 9 plots and right 1 plot.
B. The solution to the pair of inequalities is (1/2, -13/2). That is the intersection and point of the two lines. You would need to graph the two lines (see part A answer) and then find the intersection.
Hope this helps!