What is the length of one leg of the triangle?11 units11/units22 units22/2 units
1 answer:
Answer:
The length of one leg of the triangle is 22 units
Step-by-step explanation:
The complete question in the attached figure
Let
x ----> the length of one leg of the triangle
we know that
In the right isosceles triangle of the figure
The cosine of angle of 45 degrees is equal to the adjacent side to angle of 45 degrees divided by the hypotenuse
---> equation A
----> equation B
equate equation A and equation B and solve for x
therefore
The length of one leg of the triangle is 22 units
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Answer:
128.8 cm²
Step-by-step explanation:
In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.
For the small square, half of the diagonal is 4 cm, therefore the length of the diagonal is 8 cm (2 × 4 cm). Let the length of the side be a cm, using Pythagoras theorem:
a² + a² = 8²
2a² = 64
a² = 32
a = √32 = 5.7 cm
The area of the small square = length × length = 5.7 × 5.7 = 32.5 cm²
For the large square, half of the diagonal is 9 cm, therefore the length of the diagonal is 18 cm (2 × 9 cm). Let the length of the side be b cm, using Pythagoras theorem:
b² + b² = 18²
2b² = 324
b² = 162
b = √162 = 12.7 cm
The area of the large square = length × length = 12.7 × 12.7 = 161.3 cm²
The area of the shaded region = Area of large square - Area of small square = 161.3 cm² - 32.5 cm² = 128.8 cm²
