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Paha777 [63]
3 years ago
13

Sum of the second and third consecutive odd integers, simplified

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
If you know how to solve word problems involving the sum of consecutive even integers, you should be able to easily solve word problems that involve the sum of consecutive odd integers. The key is to have a good grasp of what odd integers are and how consecutive odd integers can be represented.

Odd Integers

If you recall, an even integer is always
2
2 times a number. Thus, the general form of an even number is
n
=
2
k
n=2k, where
k k is an integer.
If I am incorrect I am so sorry.:(
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I will give u brainliest
Lady bird [3.3K]

Answer:

130

Step-by-step explanation:

I don' know my explanation.

6 0
3 years ago
What are the steps to covert the answer into a mixed fraction of this problem 45 x 3/8= 135/8
riadik2000 [5.3K]
1. Divide 135 by 8 which is equal to 16
2. Multiply 16 ×8 = 128
3. Subtract 135 - 128 =7

The seven represent the numerator so it would be 7/8.

The finally answer would be

16 \ \frac{7}{8}
7 0
3 years ago
Micheal buys a basket of mangoes on sale for 4 dollars before tax. The sales tax is 12%. What is the total price Micheal pays fo
nikitadnepr [17]

Answer:

$4.48 <em>is the total price.</em>

Step-by-step explanation:

<em>Mulitply the total by the percentage.</em>

<em />

4 * .12 = .48

<em>Add those together. </em>

<em />

4 + .48 = 4.48

<em>Total price of mangoes: $</em>4.48<em> </em>

6 0
3 years ago
Another one <br>Topic: Law of Indices<br>Evaluate this;<br><br>(13⁰÷5)²​
Zarrin [17]

<u>Answer:</u>

<h2>1÷25</h2>

<u>Steps:</u>

(13⁰/5)²​

(1÷5)²

1²÷5²

1÷25

7 0
3 years ago
[Related Rates]
Orlov [11]
Below is the solution: 

A(final)=16cm^2 ds/dT=6 da/dT=? 

<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>

<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm) 
</span>
<span>Answer should be da/dT=48cm^2/sec
</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

6 0
3 years ago
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