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Tema [17]
3 years ago
9

Isaac walks 4 blocks north. Then he turns around and walks 1 block south.

Physics
1 answer:
kramer3 years ago
7 0

Answer:

Isaac walked a distance of 5 blocks, and his displacement was 3 blocks north.

Explanation:

Distance is what he covered from the beginning, while displacement was what he covered in a specific direction

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changes in the number of turns of the coil affects the deflection in the galvanometer. True or false?
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Answer:True

Explanation:Because the deflection in galvanometer is calculated by the following formula;

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Is eureka a better conductor than copper
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Nope Copper is a better conductor
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Which is an example of a chemical change?
Monica [59]

Answer:

Frying an Egg

Explanation:

When chemical bonds are broken or formed, new particles are created. Therefore, frying an egg is a chemical change because it results in the formation of new particles.

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3 years ago
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A 0.02kg dart is loaded into a toy spring gun by compressing the spring 6cm. If the spring has a constant of 20 N/m, find… a. Th
katrin2010 [14]

Answer:

a) 0.036 J b) 0.036J c) 0.036 d) 1.9m/s e) 0.18 m

Explanation:

Mass of the dart = 0.02kg, the spring was compressed to 6cm

Work needed to compress the spring = 1/2*k*x ^2 where k is the force constant of the spring in N/m, x is the distance it was compressed in m

Work needed to compress the spring = 0.5 * 20* 0.06^2 since 6cm = 6 / 100 = 0.06 m

Work needed to compress the spring = 0.036J

b) the total energy stored in the spring = the work done to compress the spring = 0.036J

c) kinetic energy of the dart as it leaves the the spring = elastic potential energy stored in the spring = the work done in compressing the = 0.036J using the law of conservation of energy; energy is neither created nor destroyed but transformed from one form to another.

d) 1/2mv^2 = 0.036

mv^2 = 0.036*2

v^2 = 0.036*2 / 0.02 = 3.6

v = √3.6 = 1.897 approx 1.9m/s

e) kinetic energy of the dart = work done against gravity to get the body to height h

Work done against gravity = potential energy conserved at height = -mgh g is negative because the motion is upward while gravity acts downward

0.036 = 0.02 * 9.81 * h

0.036 / ( 0.02*9.81) = h

h = 0.18 m

6 0
4 years ago
An object is launched upwards at an initial speed of 3 m/s. What is the maximum height reached by the object from where it was l
ollegr [7]

Answer:

the maximum height reached by the object from where it was launched is 0.4591 m

Explanation:

initial speed of the object, u= 3 m/s

The velocity at the maximum height will always be 0.

Therefore,  final velocity, v= 0 m/s  

Using the Newton's  equation of motion,

v^2 - u^2 = 2*g*h(max)

0 - u^2= 2*g*h(max)

h(max) = -u^2 /2* g

where g is the gravitational acceleration.

g= - 9.8 m/s^2

substituting the values in equation,

h(max)= - (3*3) / 2*(-9.8)

h(max) =  0.4591 m

the maximum height reached by the object from where it was launched is 0.4591 m

learn more about maximum height reached here:

<u>brainly.com/question/20001249</u>

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4 0
2 years ago
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