Answer:
an electron with element with large number of valence electron and large atomic <u>radius</u>
Answer:
The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm
Explanation:
The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:
T = d * Fp
Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:
Fp = F*sin(a)
Replacing the values for the force and the angle:
Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N
Taking the distance in meters:
T = 0.2m * 0.363 N = 0.063 Nm
<span>R² = 12² + 4² - 2*12*4cos45° </span>
<span>R² = 92.12 </span>
<span>R = 9.6 mph ===========> ANSWER </span>
<span>Use law of sines to find bearing </span>
<span>4/sinA = R/sin45° </span>
<span>sinA = 4sin45°/9.6 = 0.2946278...... </span>
<span>A = 17.14° </span>
<span>bearing = North 17.14° West or 342.86°</span>
