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2 years ago

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In △ABC, AB=9.2 ft, BC=11.9 ft, and m∠B=27°.

1 answer:

VladimirAG [237]2 years ago

8 0

To calculate the area of a triangle you need the base & the altitude to this base:

Area triangle = 1/2(B x H)

Let's draw the altitude A intersecting BC in H. WE get now a right triangle AHB. We know AG = 9.2 we know the angle B =27°, so we can find the altitude AH through trigonometry :
sin(B) = opposite side over hypotenuse
sin(27°) = AH/AB==> sin(27°) =0.454 ==0.454= AH/9.2==>AH =0.454*9.2

AH = 4.177

Area triangle ABC = (1/2) * 11.9 * 4.177= 24.85

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2 years ago

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erik [133]

Answer:

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2 years ago

kifflom [539]

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$\\ \sf\longmapsto x(x+4)+1(x+4)>0$

$\\ \sf\longmapsto (x+4)(x+1)>0$

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2 years ago

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2 years ago

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kow [346]

Answer:

Option A.

Step-by-step explanation:

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$A=x^2$ .... (1)

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$\dfrac{dx}{dt}=2$

It is given that bob currently owns 250,000 square feet of land.

Fist find the length of each side.

$A=250000$

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2 years ago