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Rudik [331]
3 years ago
9

Square root of 405, simplfiy and give the exact value

Mathematics
2 answers:
dexar [7]3 years ago
4 0
Sq. root of 405= approximately positive or negative 20.124611797498107267682563018581

Its irrational. This is as far as the calculator goes.
Sonja [21]3 years ago
4 0
Your answer without a decimal would be as follows:

9 (Sqr Root sign)5

9 is on the outside of square root sign and five is on the inside.
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What is the slope of the line through the points (4,2) and (-16,-6)
Maslowich

Answer:

2 / 5.

Step-by-step explanation:

The slope is the rise over the run.

In this case, the rise is 2 - (-6) = 2 + 6 = 8.

The run is 4 - (-16) = 4 + 16 = 20.

So, the slope is 8 / 20 = 4 / 10 = 2 / 5.

Hope this helps!

7 0
4 years ago
Read 2 more answers
Let each Square represent 1/3 unit by 1/3 unit.
Varvara68 [4.7K]
(5/3)*(7/3) = 35*(1/3)²

The area is 35 square units.
7 0
3 years ago
I really need this ASAP! what is 14 2/7 as a fraction
nlexa [21]
Multiply 14 by the denominator of the fraction.

14 • 7 = 98

Then add it to the numerator.

98 + 2 = 100

Your answer is 100/7
8 0
4 years ago
Area of a circular ring: A = 4<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " align="a
OleMash [197]
1a)      A = 4πpw
      /4πw = /4πw
  A / 4πw = p

1b) A = 4πpw
     22 = 4πp(2)
       p = 11/4π (≈0.87)

2a)        P = 2πr + 2x
      P - 2x = 2πr
        /2π      /2π
 P-2x / 2π = r

2b)    P = 2πr + 2x
      440 = 2πr + 2(110)
          r = 110/π (≈35.014)
      

      
8 0
3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
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