The given statement is proved by side-angle-side (SAS) theorem.
Yes, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle the triangles are congruent.
The statement is proved by SAS theorem
<u>Side-Angle-Side (SAS) theorem: </u>
The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.
Hence, The given statement is proved by side-angle-side (SAS) theorem.
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True.
Since
,
and the solutions are decreasing functions.
Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
So, first, what are the two sides?
let's call then x and y
we know that 2(x+y)=12.5 (that's the distance around)
so that means that x+y=6.25 (I just divided both by 2)
now, x=4y (from "4 times as long as it is wide")
so we can substitute:
x+4x=6.25
5x=6.25
x=1.25
so one side, is 1.25 and the other will be 1.25*4=5
and for the area we multiply the two:
1.25*5=6.25 square kilometers, and this is the answer!
Answer:
438976
Step-by-step explanation:
76^3
