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Sever21 [200]
3 years ago
9

CH is an altitude of the triangle ABC, m∠A = 40°, m∠B = 68°. The circle with the diameter CH intersects sides AC and BC at point

s N and M respectively. Find the measure of the angles CNM, HNM, and HMN.

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
Answer: CNM=65, HNM=47,HMN=43 I’m pretty sure these are right

Step by step solution: See photo

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katovenus [111]

Since \alpha and \beta are roots of ax^2+bx+c, we can factorize the quadratic in terms of the roots as

ax^2+bx+c = a(x-\alpha)(x-\beta)

Expanding the right side gives

ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta

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and expanding this gives

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