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3 years ago

Helpppppppppppppppppppppppppppppp

Mathematics

2 answers:

Rzqust [24]3 years ago

8 0

Answer:

Step-by-step explanation:

11-6=10-x

11-6-10=-x

-5=x

11-6=10-5

xz_007 [3.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

Simplify the left side:

11-6 = 5

Call the right side unknown, x:

Giving us 10 - x

So we have 5 = 10 - x

Now subtract 10 from both sides:

-5 = - x

Now divide both sides by -1

5 = x

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The equal value is 78125

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4 years ago

Use number line to show numbers in the solution set of the inequality 2s+ 36 greater than 50.

Tems11 [23]

s>7

So, all values greater than 7 are included in the number line.

Step-by-step explanation:

We need to use number line to show numbers in the solution set of the inequality 2s+ 36 greater than 50

Solving and finding value of s:

2s+36>50

Adding -36 on both sides

2s+36-36>50-36

2s>14

Divide both sides by 2

s>7

So, all values greater than 7 are included in the number line.

The number line is shown in figure attached below

Keywords: Solving inequalities

Learn more about Solving inequalities at:

#learnwithBrainly

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3 years ago

Which ordered pair is a solution to the equation?

mezya [45]

Answer:

Step-by-step explanation:

4(4) = -7(-3) - 5

16 = 21 - 5

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answer is D

7 0

3 years ago

Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.

Mashcka [7]

Answer:

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Step-by-step explanation:

Integration Rule:

$\int x^n dx= \frac{x^{n+1}}{n+1}+c$
$\int \frac1x dx= ln(x) +c$

Given differential equation is

$x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)$

$\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx$ [ multiplying dx both sides]

$\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx$ [ dividing $x^2\sqrt w$ both sides]

Integrating both sides

$\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx$

$\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx$

$\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx$

$\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c$ [ c is arbitrary constant]

$\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

6 0

3 years ago

Which expression is equivalent to (4+3i)^2+(6-I)^2

zhenek [66]

Answer:

$\large\boxed{(4+3i)^2+(6-i)^2=42+12i}$

Step-by-step explanation:

$(4+3i)^2+(6-i)^2\qquad\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2\\\\=4^2+2(4)(3i)+(3i)^2+6^2-2(6)(i)+i^2\\\\=16+24i+9i^2+36-12i+i^2\qquad i=\sqrt{-1}\to i^2=-1\\\\=16+24i+9(-1)+36-12i+(-1)\\\\=16+24i-9+36-12i-1\qquad\text{combine like terms}\\\\=(16-9+36-1)+(24i-12i)\\\\=42+12i$

8 0

4 years ago