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3 years ago

Helpppppppppppppppppppppppppppppp

Mathematics

2 answers:

Rzqust [24]3 years ago

8 0

Answer:

Step-by-step explanation:

11-6=10-x

11-6-10=-x

-5=x

11-6=10-5

xz_007 [3.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

Simplify the left side:

11-6 = 5

Call the right side unknown, x:

Giving us 10 - x

So we have 5 = 10 - x

Now subtract 10 from both sides:

-5 = - x

Now divide both sides by -1

5 = x

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The diameter of an average cell in a human body is 1 x 10^-5 mm. If the diameter of a pin head is 2 x 10^-2, how many body cells

Tatiana [17]

Answer:

2000

Step-by-step explanation:

diameter of an average cell= 1 x 10^-5 mm

diameter of a pin head= 2 x 10^-2

number of body cells that would fit on the pin head=2 x 10^-2 ÷ 1 x 10^-5

=2000 body cells

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3 years ago

How to do gcf vs lcm

tangare [24]

GCF stands for greatest common factor so if u have a problem like let's say, "What is the gcf of 36 and 90?" all u do is go down your multiples table and write them all down till 36 you will get 9 and if u take 10×9 it equals 90. For LCM all you do is go down your multiples table and find the least number that is the same with each other.

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3 years ago

Maria is buying a car for $18,510. She will finance $13,000 of it with a 3-year loan at 2.8% APR. What will her monthly auto pay

Eva8 [605]

Answer-

Maria's monthly payment will be $376.91

Solution-

Maria is buying a car worth of $18,510, but she will finance only $13,000 of it with a 3-year loan at 2.8% APR.

We know that,

$\text{PV of annuity}=P[\dfrac{1-(1+r)^{-n}}{r}]$

Here,

$\text{PV of annuity=13000},\\\\\text{P=??},\\\\\text{r = 2.8\%\ annually}=\frac{2.8}{12}\text{\%\ monthly}\\\\\text{n=3 years=36 months}$

Putting the values,

$\Rightarrow 13000=P[\dfrac{1-(1+\frac{2.8}{1200})^{-36}}{\frac{2.8}{1200}}]$

$\Rightarrow 13000=P\times 34.4909$

$\Rightarrow P=\dfrac{13000}{34.4909}$

$\Rightarrow P=376.91$

Therefore, her monthly payment will be $376.91

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3 years ago

Which of the following expressions are equivalent? Justify your reasoning.

Fynjy0 [20]

A. $4\sqrt{x^{3}$
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    $4\sqrt{x^{2}}\sqrt{x}$
    $4x\sqrt{x}$

b. $\frac{1}{x^{-1}} =x$

c. $10\sqrt{x^{5} * x^{4} * x^{2}}$
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    $10\sqrt{x^{10}* x}$
    $10\sqrt{x^{10}}\sqrt{x}$
    $10x^{5}\sqrt{x}$

d. $x^{\frac{1}{3}} * x^{\frac{1}{3}} * x^{\frac{1}{3}}$
    $x$

The expressions that are equivalent are B and D.

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3 years ago

Answer to the question

dangina [55]

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3 years ago