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Sav [38]
3 years ago
13

Round off then estimate 18.9*5.2

Mathematics
1 answer:
Nataly [62]3 years ago
7 0
18.9 rounded is 19
5.2 rounded is 5

19 * 5 = 95
You might be interested in
Does -3(x-4)= -3x=12 have one solution, many solutions, or no solutions at all?
TEA [102]

Answer:

If the expression is:

-3x + 12 = -3x + 12, infinite solutions

If the expression is:

-3x + 12 = -3x - 12, no solutions

Step-by-step explanation:

Step 1: Distribute

-3x + 12 = 3x = 12

If both lines have the same slope and same y-int, they are the same line and therefore have infinite solutions.

If both lines have the same slope but different y-int, then they are parallel and therefore have no solutions.

4 0
2 years ago
Does anyone know the answer
AlexFokin [52]
1/8, 2/16, Equivalent fractions can be found by multiplying or dividing both the numerator and the denominator by the same number.
4 0
3 years ago
Read 2 more answers
On a baseball team, the ages of each of the players are as follows: 21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33;
Paul [167]

Answer:

Mean = 30.68

Standard deviation = 6.095

Two standard deviations above the mean = 42.87

Step-by-step explanation:

Given the following data :

21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33; 34; 35; 36; 36; 36; 36; 38; 38; 38; 40

Mean = Σ(x) / n

n = 25

Σ (X) = 767

Mean (m) = 767 / 25

Mean (m) = 30.68

Standard deviation : sqrt[Σ(x - m) / n]

Using a calculator :

Standard deviation = 6.095 ( 2 decimal places)

2 standard deviations above the mean :

Mean + 2(standard deviation)

Mean + 2(6.095)

30.68 + 12.19

30.68 + 12.19

= 42.87

6 0
3 years ago
1.
mars1129 [50]

Answer:

yes they are

Step-by-step explanation:

they are both congruent because they are the same shape and size, they are just on opposite sides

(congruent means that 2 objects are the same shape and size)

3 0
2 years ago
Read 2 more answers
Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14 times c^2-c-2/c^2-2c-15
Citrus2011 [14]

Answer: c ≠ {-7, -3, 2, 5}

<u>Step-by-step explanation:</u>

  \frac{c^{2} - 3c - 10}{c^{2} + 5c - 14} * \frac{c^{2} - c - 2}{c^{2} - 2c - 15}

= \frac{(c - 5)(c + 2)}{(c + 7)(c - 2)} * \frac{(c - 2)(c + 1)}{(c - 5)(c +3)}

restrictions:

c + 7 ≠ 0           c - 2 ≠ 0          c - 5 ≠ 0          c + 3 ≠ 0

    c ≠ -7                 c ≠ 2               c ≠ 5                c ≠ -3

3 0
3 years ago
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