Answer:
3/2
Step-by-step explanation:
We can use the slope formula to find the slope of the line
m = ( y2-y1)/(x2-x1)
Using the points (0,-4) and (2,-1)
m = ( -1 - -4)/( 2 - 0)
= (-1+4)/ (2 -0)
= 3/2
Given:
- the perimeter of a rectangular field is 84 yards
- the ratio of the length to the width is 2:1
To find:
- the length
- the width
- the area
Answer:
Let's assume that the length is 2x and the width is 1x.
We know that the formula to find the perimeter of a rectangle is as follows:
Perimeter = 2 × (Length + Width)
Substituting the values that we have, into the formula above,
84 = 2 × (2x + 1x)
84 = 2 × 3x
84/2 = 3x
42 = 3x
x = 42/3
x = 14
Since we know the value of 'x', let's use it to find the length and the width.
Length = 2x = 2 × 14 = 28
Width = 1x = 1 × 14 = 14
Since we now know the length and the width, let's find the area of the rectangle.
The formula to find the area of a rectangle:
Area = Length × Width
Substituting the values we have into the formula,
Area = 28 × 14
Area = 392
Therefore, the area of the rectangle is 392 square yards.
Hope it helps. :)
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
there ain't nun to answer here
Step-by-step explanation:
Observe attached picture.
On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft
When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.
We can apply trigonometry rules to find height of flagpole.
From small triangle containing sign we can find tangens function:

Similarly we can do for large triangle containing flagpole:

We see that these two equations have same left sides. This means that their right sides must also be same:

We can solve for A:

Height of flagpole is 48 feet.