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Marina CMI [18]
3 years ago
14

The perimeter of a rectangular field is 84 yards. The ratio of the length to the width is 2:1. What are the length, width and ar

ea of the field?
Mathematics
1 answer:
Ivenika [448]3 years ago
4 0

Given:

  • the perimeter of a rectangular field is 84 yards
  • the ratio of the length to the width is 2:1

To find:

  • the length
  • the width
  • the area

Answer:

Let's assume that the length is 2x and the width is 1x.

We know that the formula to find the perimeter of a rectangle is as follows:

Perimeter = 2 × (Length + Width)

Substituting the values that we have, into the formula above,

84 = 2 × (2x + 1x)

84 = 2 × 3x

84/2 = 3x

42 = 3x

x = 42/3

x = 14

Since we know the value of 'x', let's use it to find the length and the width.

Length = 2x = 2 × 14 = 28

Width = 1x = 1 × 14 = 14

Since we now know the length and the width, let's find the area of the rectangle.

The formula to find the area of a rectangle:

Area = Length × Width

Substituting the values we have into the formula,

Area = 28 × 14

Area = 392

Therefore, the area of the rectangle is 392 square yards.

Hope it helps. :)

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2 years ago
What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





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Read 2 more answers
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