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3 years ago

11

Last month Kim trained 3 times as many dogs as cats. If the total number of cats and dogs she trained is 24, how many cats did K

im train? Complete the equation and solve.

1 answer:

LenaWriter [7]3 years ago

3 0

Answer:

6

Step-by-step explanation:

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Slope and equation, how much battery does she lose an hour

insens350 [35]

Equation: y=-5x+100, where x is the number of hours and y is the battery percentage
The slope is -5, meaning she loses 5% of battery per hour
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3 years ago

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Solve for x:<br> -14x > -3

Alexus [3.1K]

Answer:

x>11

Step-by-step explanation:

-14x>-3

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3 years ago

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3 years ago

Jack and Jill are trying to find the slope of a line segment connecting two points, (x1, y1) and (x2, y2). Jack uses the formula

Nikolay [14]

The correct question is
<span>Jack and Jill are trying to find the slope of a line segment connecting two points, (x1, y1) and (x2, y2). Jack uses the formula m = (y2 - y1)/( x2 - x1) . Jill mistakenly uses a different formula, but still gets the right answer. Which formula COULD she have used? A) (x2 - x1)/( y2 - y1) B) (y1 - y2)/( x1 - x2) C) (x1 - x2)/( y2 - y1) D) (y2 - y1)/( x1 - x2)

we know that

the correct formula to calculate the slope is
m=(y2-y1)/(x2-x1)
then
</span><span>if both numerator and denominator multiply it by -1
</span>
m=-(y2-y1)/-(x2-x1)---------> m=[-y2+y1]/[-x2+x1]
m=[y1-y2]/[x1-x2]

therefore

the answer is the option
B) (y1 - y2)/( x1 - x2)

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3 years ago

You are running a fuel economy study. One of the cars you find is blue. It can travel 44 and one half miles on 1 and one fourth

Radda [10]

Unit rate of blue car is 35.6 miles/gallon and unit rate of red car is 36 miles/gallon. The red car could travel the greater distance on 1 gallon of gasoline.

<u><em>Explanation</em></u>

Unit rate for each car can be calculated using the below formula...

Unit rate = (Distance traveled) / (Amount of gasoline)

For Blue car, distance traveled $=44\frac{1}{2} = \frac{89}{2} miles$ and amount of gasoline $=1 \frac{1}{4}= \frac{5}{4} gallons$

So, the unit rate for blue car = $\frac{89}{2}$ ÷ $\frac{5}{4}$ = $\frac{89}{2}$ × $\frac{4}{5}$ = $\frac{356}{10} = 35.6$ miles/gallon

Now for Red car, distance traveled $= 28\frac{4}{5} = \frac{144}{5} miles$ and amount of gasoline $= \frac{4}{5} gallons$

So, the unit rate for red car = $\frac{144}{5}$ ÷ $\frac{4}{5}$ = $\frac{144}{5}$ × $\frac{5}{4}$ = $\frac{144}{4} = 36$ miles/gallon

As the unit rate for red car is greater than the blue car, that means the Red car could travel the greater distance on 1 gallon of gasoline.

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3 years ago