Answer:
a. 49.5 and 54.5
Step-by-step explanation:
Class interval is a range of a value that is used to group data into equal size for easy analysis and representation of the data. It is applicable in the divisions of a histogram or bar chart into classes. Examples of class interval are 50-54, 55-59, 60-64, 65-69, 70-74 etc.
Class limit is the minimum and maximum value the class interval may contain. The minimum value is called the lower class limit and the maximum value is called the upper class limit. For class interval 50-54, the lower class limit is 50 and the upper class limit is 54.
Class boundaries are the numbers used to separate classes. It is the real limits of a class. For non-overlapping classes, the lower class boundary of each class is calculated by subtracting 0.5 from the lower class limit. The upper class boundary of each class is calculated by adding 0.5 to the upper class limit. Example: For class interval 50-54, the lower class boundary is 49.5 and the upper class class boundary is 54.5
Considering the question given, to get the real limits of the interval 50-54, 0.5 is subtracted from the lower class limit to give 49.5. Also, 0.5 is added to the upper class limit to give 54.5.
By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.
<h3>How to calculate the quantity of coins in a collection</h3>
In this question we know the quantity of coins in a box and such coins are part of the <em>coin</em> collection. By definition of percentage we have the <em>total</em> quantity of coins in the collection:
x = 10*(100/20)
x = 50
By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.
To learn more on percentages: brainly.com/question/13450942
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To solve this we are going to graph each one of the system of equations. The points in which the graphs of the tow equations intercepts will be the real solutions of the system of equations.
System A. Since the graph of the equations intercepts two times, we can conclude that the system has
2 real solutions.
System B. Since the graph of the equation don't intercept, we can conclude that the system has
0 real solutions.
System C. Since the graph of the equations intercepts two times, we can conclude that the system has
2 real solutions.
Answer:
y=14
Step-by-step explanation:
solve for y by simplifying both sides of the equation then insolating the variable
