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kkurt [141]
3 years ago
14

What is the LCD of 2/5 and 4/11

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0
To find the lowest common denominator you need to know the factors of 5 and 11.
So make two lists:
5, 10, 15, 20, 25, 30, and so on.
11, 22, 33, 44, 55, 66, and so on.
Keep doing that until you find the lowest common number in the lists. The LCD will be 55.
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Please help!!!!!!!!!!!!!!!
babunello [35]

Answer:

Answer A

Step-by-step explanation:

Answer A indicates some minimal value for the set of points to the left (negative side of the distribution) which are associated with negative skewness since the mean is at 22 also with larger deviation to the left shown in the median of the points to the left further to the negative side of the plot.

Answers B and C show symmetric distributions (no skewness at all).

Answer D would represent skewness to the right (positively skewed)

So the correct answer is answer A.

8 0
4 years ago
Complete the function table below function<br> f(x) = 6x -3
taurus [48]
When x is equal to -1:
f(-1)=6(-1)-3
=-7-3
=-10
y=-10

When x is equal to 0:
f(0)=6(0)-3
=0-3
=-3
y=-3

When x is equal to 1:
f(1)=6(1)-3
=6-3
=3
y=3

When x is equal to 2:
f(2)=6(2)-3
=12-3
=9
y=9
6 0
3 years ago
In the game of​ roulette, a player can place a ​$4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal
creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}

E(x)=\frac{140-148}{38}

E(x)=\frac{-8}{38}=-$0.2105

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0
3 years ago
Three students out of a group of 10 seniors will be chosen to speak in front of the school. What is the probability that Ben, Ma
Ivenika [448]
What can you pick like A B C D
8 0
3 years ago
Read 2 more answers
Scientific Notation<br> 7.28 x 10^10
Vsevolod [243]

Answer:

72800000000

Step-by-step explanation:

7.28 * 10^10 = 72800000000

7 0
3 years ago
Read 2 more answers
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