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Answer:
Step-by-step explanation:
A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .
So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .
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When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.
That is ,
This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .
Answer:
Step-by-step explanation:
Translation of a point (h, k) by 'a' units to the right and 'b' units upwards is defined by,
(h, k) → (h + a, k +b)
Coordinates of A → (-4, -2)
Coordinates of B → (1, -1)
Coordinates of C → (0, -5)
If these points are shifted 4 units right and 3 units up,
By applying rules of the translation,
Coordinates of image point A' → (-4 + 4, -2 + 3)
→ (0, 1)
Coordinates of B' → (1 + 4, -1 + 3)
→ (5, 2)
Coordinates of C' → (0 + 4, -5 + 3)
→ (4, -2)
Now plot these points on the graph.
Answer: Yes, the given set of vectors is a basis of R³.
Step-by-step explanation: We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :
B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .
For a set to be a basis of R³, the following two conditions must be fulfilled :
(i) The set should contain three vectors, equal to the dimension of R³
and
(ii) the three vectors must be linearly independent.
The first condition is already fulfilled since we have three vectors in set B.
Now, to check the independence, we will find the determinant formed by theses three vectors as rows.
If the value of the determinant is non zero, then the vectors are linearly independent.
The value of the determinant can be found as follows :
Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.
Thus, the given set is a basis of R³.