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Assoli18 [71]
4 years ago
14

Honestly do not understand?!?!

Chemistry
1 answer:
GarryVolchara [31]4 years ago
3 0
I think they are all incorrect honestly most of them are fake.
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I'm sorry but I can't go deeper into explaining as that's a tough question.
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What is 5.2034 x 10^8 in standard format
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A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un
GaryK [48]

Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = 4.81J/g^oC

T_1 = initial temperature  = 22.7^oC

T_2 = final temperature  = 19.4^oC

Now put all the given value in the above formula, we get:

Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC

Q=-23.8095J=-0.0238kJ

Now we have to calculate the heat of the reaction in kJ/mol.

\Delta H=\frac{Q}{n}

where,

\Delta H = enthalpy change = ?

Q = heat released = 0.0238 kJ

n = number of moles NH₄NO₃ = \frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{1.50g}{80g/mol}=0.01875mole

\Delta H=\frac{0.0238kJ}{0.01875mole}=1.27kJ/mole

Therefore, the heat of the reaction is, 1.27 kJ/mole

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Which would be easier to train,ligers or tigons? cite the text​
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Answer:

Tiger

Explanation:

Where is the text so I can Cite the Text

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