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3 years ago

What is 5.2034 x 10^8 in standard format

Chemistry

2 answers:

777dan777 [17]3 years ago

8 0

Five hundred twenty million, three hundred and forty thousand. hope it helps!

Elanso [62]3 years ago

6 0

The answer is 4162720
hop this works than anyone else

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Salt water can be desalinated by distillation. How much energy is needed to convert 175 g of salt water at 28.0 °C to water vapo

Vinil7 [7]

Answer:

$\Delta H=4.63x10^{5}J=463kJ$

Explanation:

Hello,

In this case, we find the following states:

a. Liquid salt water at 28.0 °C.

b. Liquid salt water at 102.5 °C.

c. Vapor salt water at 102.5 °C.

The first process (1) is to heat the liquid water from 28.0 °C to 102.5 °C and the second one (2) to vaporize the liquid salt water. In such a way, each process has an amount of energy that when added, yields the total energy for the process as shown below:

$\Delta H=\Delta H_1+\Delta H_2\\\Delta H=mCp\Delta T+m\Delta _VH\\\Delta H=175g*5.19\frac{J}{g*K}*(375.65K-301.15K)+175g*2.26\frac{kJ}{g} *\frac{1000J}{1kJ} \\\Delta H=4.63x10^{5}J=463kJ$

Best regards.

4 0

3 years ago

NaCl has a Delta. Hfus = 30. 2 kJ/mol. What is the mass of a sample of NaCl that needs 732. 6 kJ of heat to melt completely? Use

tia_tia [17]

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

The heat of fusion has been the amount of heat required to convert 1 mole of substance into solid to liquid state.

The heat required has been given as:

$Q=m\Delta H$

<h3>Computation for the mass of NaCl</h3>

The given solution has heat of fusion, $\Delta H_{fus}=30.2\rm kJ/mol$

The heat required to melt the sample has been, $Q=732.6\;\rm kJ/mol$

Substituting the values for the mass of NaCl

$\rm 732.6\;kJ/mol=Mass\;\times\;30.2\;kJ/mol\\\\
Mass=\dfrac{732.6}{30.2}\;g\\\\
 Mass=24.3\;g\\$

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

Learn more about heat of fusion, here:

brainly.com/question/87248

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MariettaO [177]

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