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Law Incorporation [45]
3 years ago
12

Please help me with #s 1 - 2- 3 and 6 I need it for today thank you

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0
1. Ten thousands
3.240
2. 1,431
(hopefully this helps)
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Y=-5x+145 5x+1y=145<br><br>a- (10,95)<br>b- no solution<br>c-(20,45)<br>d- infinitely many
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Answer: The answer is infinity solutions.

Step-by-step explanation: y=-5x+145, y=5x+y

y=-5x+145

y=5x+y

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x=-y-145/5,0

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1. -6x + 3y = 6<br> -4x + 2y = -10<br> Solve by substitution method
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There are 50 students in a calculus class. The amount of time needed for the instructor to grade a randomly chosen midterm exam
natta225 [31]

Answer:

14.46% probability that the instructor can finish grading in 4 and a half hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of n values from a distribution, the mean is n\mu and the standard deviation is s = \sqrt{n}\sigma

In this problem, we have that:

\mu = 6*50 = 300, s = \sqrt{50}*4 = 28.2843

What is the probability that the instructor can finish grading in 4 and a half hours

Four and half hours is 4.5*60 = 270.

So this probability is the pvalue of Z when X = 270.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{270 - 300}{28.2843}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

14.46% probability that the instructor can finish grading in 4 and a half hours

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Suppose that you have 8 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards without replace
posledela
7 green and 1 yellow because of the chance
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