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neonofarm [45]
3 years ago
5

Suppose the radius of a circle is 5.what is its diameter

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0
The diameter would be twice 5, or 10
scoray [572]3 years ago
6 0
5*pisquared is how you solve it

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What is equivalent to<br> 2(x-5)+4x-18=4x
Mashcka [7]
2x-10+4x-18=4x
6x-28=4x
2x=28
x=14 is the solution
6x-28=4x is equivalent

Hope this helped!
7 0
3 years ago
A student is trying to solve the system of two equations given below:
SpyIntel [72]

Answer:

c is the answer since you are trying to make the ys number (-/+) of the value the other y contains

(3) so you will multiply the first equation by -3 to be able to eliminate y

4 0
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PLEASE HELP AND TELL ME HOW YOU DID IT I HAVE TO SHOW work !! Jeans are on sale for 40% off the jeans Justin wants to buy them m
Harman [31]
Okay, if the jeans were originally $80, take 40% off of that (40% of 80 is 32) so you’d get 48. Now take 48 and multiply by 1.07 (to get 107% of the $48, to find a percentage you can move the decimal place left 2 digits and multiply), so Justin would pay $51.36 in total.
8 0
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Replace? with =, &gt;, or &lt; to make the statement true. 16 ÷ 4 + 12? 4 + 24 ÷ 2
AleksAgata [21]
<em><u>16/4+12 ? 24/2</u></em>
<em><u>4+12 ? 12</u></em>
<em><u>16 ? 12</u></em>
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6 0
3 years ago
The base of a prism has n sides. Find the numbers of faces, edges, and
Harman [31]

Answers:

  • faces = n+2
  • edges = 3n
  • vertices = 2n

===========================================================

Explanation:

Think of a hexagonal room with n = 6 walls, i.e. the floor is a hexagon with n = 6 sides. The floor and ceiling are parallel to each other, and congruent hexagons. That's 2 faces so far. Then we have another 6 faces to account for the walls. This gives 2+6 = 8 faces of a hexagonal prism.

In more general terms, a prism with a base of n sides will have 2 parallel and congruent base faces, and n walls or lateral faces. This gives n+2 total faces.

------------------------

Let's go back to the hexagonal prism. The floor has 6 sides to it, and so does the ceiling. We have 6+6 = 12 edges so far. Then we have another 6 edges where each of the rectangular walls meet up. That gives 12+6 = 18 edges total of this hexagonal prism room.

For any more general case, each base has n sides. That gives 2n sides so far for just the bases. Then add on another n for the lateral edges and we get 3n total edges.

--------------------------

Once again lets revisit the room with the hexagonal floor and ceiling. The floor has 6 vertices and the ceiling has the same vertex count. Therefore, this prism has 6+6 = 12 vertices.

For the general case, each base has n vertices. There are 2 such identical bases giving 2n vertices total.

---------------------------

One way to check the answer:

We could use Euler's Polyhedron Formula which is

F+V-E = 2

where,

  • F = number of faces
  • V = number of vertices
  • E = number of edges

For the hexagonal prism we found

  • F = 8
  • V = 12
  • E = 18

Then notice how

F+V-E = 2

8+12-18 = 2

20-18 = 2

2 = 2

This confirms the formula works for a hexagonal prism.

Now let's check it for the more general case

We found earlier that,

  • F = n+2
  • V = 2n
  • E = 3n

So,

F+V-E = 2

n+2+2n-3n = 2

3n-3n+2 = 2

0n+2 = 2

0+2 = 2

2 = 2

This helps confirm the answer for any prism with the base of n sides.

4 0
2 years ago
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