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neonofarm [45]
3 years ago
5

Suppose the radius of a circle is 5.what is its diameter

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0
The diameter would be twice 5, or 10
scoray [572]3 years ago
6 0
5*pisquared is how you solve it

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What are the verter and x-intercepts of the graph of the function given below?<br> y=x2-2x-35
horsena [70]

For x intercepts, plug in 0 for y.

               0 = (x^2) - 2x - 35

*factoring* = (x-7)(x+5)

x intercepts = 7,-5

As for the vertex, you can use the equation -b/2a for the x-coordinate of the vertex

so,

x = -b/2a = -(-2)/2 = 1

then just find the y value by plugging it back in to the equation.

y = ((1)^2) - 2(1) - 35

= -36

so, vertex is at (1,-36)

5 0
3 years ago
Scupper Molly invested $1,800 semiannually for 23 years at 8% interest compounded semiannually. What is the value of this annuit
Shtirlitz [24]

Answer:

the amount of a $3,000.00 annuity due at 12 percent compounded semiannually for 3 years. A. $334,321.00 B. $43,068.93 C. $22,180.50 D. $41,814.50

3 0
2 years ago
On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p
notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}

Now,

Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

7 0
3 years ago
Evaluate this expression if a = 2, b = -1 and c = 1.
labwork [276]
Substitute the values into the equation

2(2)+4(-1)-5(1)
4-4-5
-5
8 0
3 years ago
Read 2 more answers
Find the area of the unshaded reason for these two problems​
Taya2010 [7]

9514 1404 393

Answer:

  a) 96 m²

  b) 26,000 ft²

Step-by-step explanation:

The area of the unshaded region is the difference between the overall area of the rectangle and the area of the shaded region. It can also be found directly using the dimensions of the unshaded region.

a) We have the height of the right triangle, but need to know its base. The Pythagorean theorem can help with that. Let the base of the triangle be represented by x. Then ...

  x² +16² = 20²

  x² = 400 -256 = 144

  x = √144 = 12

The area of the unshaded triangle is given by the formula ...

  A = (1/2)bh

  A = (1/2)(12)(16) = 96 . . . . square meters

__

b) The shaded area at upper left is a square 100 ft on a side. Its area is ...

  A = s² = (100 ft)² = 10,000 ft²

The shaded area at upper right is a triangle with base and height 120 ft and 150 ft. Its area is ...

  A = (1/2)bh = (1/2)(120 ft)(150 ft) = 9,000 ft²

The area of the overall rectangle is ...

  A = LW = (300 ft)(150 ft) = 45,000 ft²

So, the unshaded area is ...

  unshaded area = overall area - left shaded area - right shaded area

  unshaded area = 45,000 ft² -10,000 ft² -9,000 ft² = 26,000 ft²

7 0
3 years ago
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