Question

A penny, nickel, and dime are simultaneously flipped. What is the probability that heads are showing on at least 6 cents worth of coins

Answer 1

Answer:

5/8

Step-by-step explanation:

The number of possible outcomes after flipping 3 coins is $2 \times 2 \times 2 = 8$. If the dime isn't heads, we need both the penny and nickel to be heads. If the dime is heads, the other two could be anything. So there are a total of $1+(2 \times 2)=5$ ways for us to get at least 6 cents. The answer is $\boxed{\dfrac58}.$