Question:
A cafeteria offers oranges, apples, or bananas as its fruit option. It offers peas, green beans, or carrots as the vegetable option. Find the number of fruit and vegetable options. If the fruit and the vegetable are chosen at random. what is the probability of getting an orange and carrots? Is it likely or unlikely that a customer would get an orange and carrots?
Answer:
The probability of getting an orange and carrots is
Step-by-step explanation:
The fruits offered in cafeteria = oranges, apples, or bananas.
The vegetables offered in cafeteria = peas, green beans, or carrots.
There are 3 fruits and 3 vegetables . Therefore the total possible number of outcomes is = = 9
Now the probability of getting an orange and carrots =
The possibility is very unlikely to happen
<span>For a box with x chocolates, the cost of packaging is C(x) = x^2 and the
weight is W(x) = x + 2. Thus the cost per unit weight is C(x) / W(x) = x^2 / (x + 2)</span>
Answer:
32
Step-by-step explanation:
Pythagorean theorem
a = perpendicular
b = base
c = hypotenuse
we have to find the hypotenuse
so,
Answer: The equation will be set up as y=mx+b. Mrs. Jones charges $35 per hour, so we can substitute m for 35 with x representing the number of hours. The $35 for pool usage fee will be substituted for b.
The answer then is y=35x+35
Answer:
7 more boys
Step-by-step explanation:
Given
Required
Number of more boys than girls in group 2
Represent the number of boys in group 1 with B and the number of girls with G.
So:
Make G the subject
The number of girls in group 2 will be:
Total number of girls (33) - number of girls in group 1(40 - B)
So, we have:
<em>This means that there are 7 more boys than girls</em>