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gavmur [86]
4 years ago
12

What is the degree of the polynomials w3-2w+w-5

Mathematics
1 answer:
yuradex [85]4 years ago
7 0
16w because you need to add it up
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Help me get the anwser to this Equation
Mariana [72]

Answer:

The answer depends on x.value

Step-by-step explanation:

I. It's linear equation

          y = mx + b

when y is output, x is input, m is slope and b is addition

   So if x = -1

          y = -4/3(-1) - 2

             = 4/3 - 2

             = (4-6)/3

           y = -2/3

   It will be something like this (-1, -2/3) when -1 is x.value, -2/3 is y.value        

You can given x.value be anything like 0, 1, 2, 3 the graph will be like this

(Picture is only example)

6 0
3 years ago
John can complete a paper route in 20 minutes. Steve can complete the same route in 30 minutes. How long will it take them to co
jek_recluse [69]
12 minutes to complete the route together
6 0
3 years ago
Read 2 more answers
Divide.<br> -6:31<br> Enter your answer as a mixed number, in simplified form, in the box.
jekas [21]

Answer:−

-12/31

Step-by-step explanation:

8 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
HELP!!! 50 POINTS!! I WILL REPORT IMPROPER ANSWERS!!!
lapo4ka [179]

Answer & Explanation:

1.) Which function is a linear function?

   The answer is B. y+7=5x

2.) If the function y=x^a-31 is a linear function, what is the value of a?

   The answer is A. 1

3.) What type of function is the function representing Sully's speed?

   The answer is C. It is a nonlinear function.

hope this helps :)

5 0
3 years ago
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