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Feliz [49]
3 years ago
8

Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t

ime and a half Last weekend Jarvis worked for six hours on Saturday and five hours on Sunday. How much more Jarvis paid last weekend altogether?
Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer: He is paid $90 last weekend.

Step-by-step explanation:

Since we have given that

Amount he earns per hour = $6

If he works on Saturday, he is paid time and a quarter .

Amount would be

6\times 1.25=\$7.5

If he works on Sunday, he is paid time and a half.

Amount would be

6\times 1.5=\$9

Number of hours he worked on Saturday = 6 hours

Number of hours he worked on Sunday = 5 hours

So, Total amount he is paid last weekend altogether is given by

6\times 7.5+5\times 9\\\\=\$90

Hence, he is paid $90 last weekend.

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Solve the following system of equations.<br> 5x+2y =-6<br> 3x-2y = 22
katen-ka-za [31]

Answer:

5x+2y =-6 ........1

3x-2y = 22 ........2

Add both Equations

we get

8x = 16

Divide both sides by 8

x = 2

Substitute x = 2 into any of the equations

3(2) - 2y = 22

-2y = 22 - 6

- 2y = 18

Divide both sides by -2

y = - 9

x = 2 y = - 9

Hope this helps

6 0
3 years ago
Consider these three squares with known area 25, 144,169
hram777 [196]

Answer:

Step-by-step explanation:

three squares with known area 25, 144,169...

1) area of the square =25

Side ×side=25

Side^2=25

Side=√25

Side =5.

Answer is 5.

2) area of the square =144

Side ×side=144

Side^2=144

Side=√144

Side =12

Answer is 12.

3)area of the square =169

Side ×side=169

Side^2=169

Side=√169

Side =13

Answer is 13.

6 0
3 years ago
Which equation is not equal to 6^3/6^6 ?: 1/6^2 6^-3 1/216 1/6^3
SCORPION-xisa [38]
The answer would be 60 because its multiplication all those numbers

4 0
3 years ago
Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
The age of trees in a forest is known to be approximately normal with an average age of 40 years and a standard deviation of 10
Keith_Richards [23]

Answer: D. -0.6

Step-by-step explanation:

Z score formula= x-mean/ SD

34-40/10= -3/5= -0.6

6 0
3 years ago
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