The answer is -19 1/2 feet
Please I think the question is not complete
Answer:
the formulae given do not make sense.
Step-by-step explanation:
Answer:
Since sine of all angles are always less than one, this shows there is no possible way to have an angle C. Thus it is impossible to have a triangle ABC with the given properties of side lengths b=3 inches and c= 5 inches to have angle B =45 degrees.
Step-by-step explanation:
In the attached drawing, each of the tic-marks are equal and
represent 1 inch each. The angle B has measure 45. We can
see by the arc that the line AC, which equals 3 inches, is
not long enough to reach the slanted side of the 45 angle.
Therefore triangle ABC is not possible. We can also show
by the law of sines that no triangle ABC with the given
properties in possible.
The standard form of a quadratic function is y = 3/2x² + 17/2x - 7
<h3>How to determine the
quadratic equation?</h3>
From the question, the points on the quadratic equation are given as
(2,4), (3,5) and (4,3)
The standard form of a quadratic equation is represented as
y = ax² + bx + c
So, we have
Point (2,4):
4a + 2b + c = 4
Point (3,5):
9a + 3b + c = 5
Point (4,3):
16a + 4b + c = 3
Solving using an online calculator. we have
a = 3/2, b = 17/2 and c = -7
Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c
y = 3/2x² + 17/2x - 7
Hence, the equation is y = 3/2x² + 17/2x - 7
Read more about quadratic equation at
brainly.com/question/1214333
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