What is b plus 14 written a expression
1 answer:
You might be interested in
Answer:
Part 1)
The y-intercept is the point (0,-1)
The x-intercept is the point (1/3,0)
The graph in the attached figure N 1
Part 2) The graph in the attached figure N 2 (see the explanation)
Part 3) see the explanation
Step-by-step explanation:
Part 1) Determine the x and y intercepts of the linear equation 3x-y-1=0. Use the intercepts to graph the line
we have
step 1
Find the y-intercept
The y-intercept is the value of y when the value of x is equal to zero
so
For x=0
The y-intercept is the point (0,-1)
step 2
Find the x-intercept
The x-intercept is the value of x when the value of y is equal to zero
so
For y=0
The x-intercept is the point (1/3,0)
step 3
To graph the line, plot the intercepts and join then
The graph in the attached figure N 1
Part 2) Determine the slope and Y intercept of the linear equation 3X minus Y minus one equals zero use the slope and Y intercept to graph the line. On your graph, label the point that represents the Y intercept and one additional point found by applying the slope of the line.
we have
isolate the variable y
Adds y both sides
This is the equation of the line in slope intercept form
where
m is the slope
b is the y-intercept
we have
so
The y-intercept is the point (0,-1)
Point and a slope to graph the line
the point is (0,-1)
the slope is m=3
Remember that the formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)
rise=3
run=1
so
To graph the line
1. Plot the point (0,-1).
2. From that point, count right 1 unit and up 3 unit and plot a second point.
(0+1,-1+3)
(1,2)
3. Draw a line through the two points
we have
(0,-1) and (1,2)
The graph in the attached figure N 2
Part 3) In the form of a paragraph, compare and contrast the methods used for graphing the linear equation 3x-y-1=0 in Parts 1 and 2
In the first method, we use the intercepts to plot the line (see the explanation part 1)
In the second method, we use the y-intercept and the slope in order to have two points and thus be able to graph the line (see the explanation Part 2)
By comparing and contrasting the two methods, we can see that the graph obtained is the same
