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Ad libitum [116K]
3 years ago
12

A person 5 ft tall casts a shadow 13ft long. At the same time a nearby tree casts a shadow 37 ft long. Find the height of the tr

ee
Mathematics
2 answers:
jeyben [28]3 years ago
7 0
The height of the tree is 45 ft long
ANTONII [103]3 years ago
4 0

\frac{5}{13}  =  \frac{x}{37}
try using that equation
explanation - the height of the tree/person goes on top. the length of the shadow goes on the bottom. these two "triangles" are likely congruent, so they should be to scale (the sun strikes every object at the same time).
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A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
Consider the set T = {1, 2, 3, 4, 5, 6}. Let R = {(a, b) | a divides b} be a relation on the set T. Identify the missing ordered
serg [7]

Answer:  The missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

Step-by-step explanation:  We are given the following set :

T = {1, 2, 3, 4, 5, 6}.

And, R = {(a, b) | a divides b} be a relation on the set T.

We are to identify the missing pairs from the following list of all ordered pairs in the given relation R on the set T :

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), _____, (4, 4), (5, 5), and (6, 6).}.

Since R contains the ordered pairs (a, b) such that a divides b, so all the ordered pairs in R are

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 2), (2, 4), (2, 6), (3, 3), (3, 6), (4, 4), (5, 5), and (6, 6).

Thus, the missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

4 0
3 years ago
Which equations show the identity property of multiplication?
Lady bird [3.3K]
My answer is a and c becuase they equal the same on each side
3 0
3 years ago
HELP PELASE!!!!!!!! THESE ARE DUE SOON and a grade
likoan [24]
Answer: 6,400 Explanation: there is 3200 ounces in one ton so i took that and divided it by 5
3 0
2 years ago
Read 2 more answers
Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a
Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature  delta(t1) = 10 degrees

mc delta(t) = m1 * c * delta(t1)

m = 100

m1 = 50 grams.

c is going to be divided out

we'll solve for the ratio of delta(t) / delta(t1)

100 * delta(t) = 50 (delta(t1)

100 * delta(t) = 50*10

delta(t) = 50*10/100

delta(t) = 5 degrees.

Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.

The 100 gram mass only rises 5 degrees.

The 50   gram mass rises 10 degrees.

7 0
3 years ago
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