Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
g(x) = 1/2*(4)^(–x) and
g(x) =1/2*(1/4)^(x)
Please, see attached picture.
Step-by-step explanation:
Your full question is attached in the picture below
To easily solve this problem, we can graph each equation and see, which one represents a reflection of the function over the y axis.
See, second image.
The answers are
g(x) = 1/2*(4)^(–x) and
g(x) =1/2*(1/4)^(x)
The slope of the equation is 4
Answer:
a is 3x
b is 6(8y-5) and 6x8y-6x5
Step-by-step explanation:
first a is 3x
b is 6(8y-5) 6x8y-6x5
