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Lena [83]
3 years ago
7

Which describes bonding electrons in a polar covalent bond?

Physics
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

Electrons that are not shared equally

pickupchik [31]3 years ago
5 0
Polar covalent bonding is a type of chemicalbond where a pair of electrons is unequally shared between two atoms. In a polar covalent bond, the electrons are not equally shared because one atom spends more time with the electrons than the other atom.

Hope this helps :)
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A horizontal vinyl record of mass 0.10 kg and radius 0.10 m rotates freely about a vertical axis through its center with an angu
Tresset [83]

Answer:

The angular speed of the record is 3.36 rad/s.

Explanation:

Given that,

Mass of record= 0.10 kg

Radius = 0.10 m

Angular speed = 4.7 rad/s

Moment of inertia I=5.0\times10^{-4}\ kgm^2

Mass of putty = 0.020 kg

We need to calculate the angular speed

Using law of conservation of momentum

L_{i}=L_{f}

I\omega_{i}=(I+mr^2)\omega_{f}

\omega_{f}=\dfrac{I\omega_{i}}{(I+mr^2)}

Put the value into the formula

\omega_{f}=\dfrac{5.0\times10^{-4}\times4.7}{5.0\times10^{-4}+0.020\times(0.10)^2}

\omega_{f}=3.36\ rad/s

Hence, The angular speed of the record is 3.36 rad/s.

3 0
4 years ago
If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the
Novosadov [1.4K]
<span>Law of Conservation of Energy states that the total amount of energy remains constant in an isolated system and Energy can be neither created nor destroyed.
</span>
Therefore,
<span>The refrigerator</span><span> removed 272 Joules of energy from the food (making it colder) and dumped 272 J of energy outside (heat of the refrigerator).</span>
3 0
3 years ago
Witch of the following is not considered to be a greenhouse gas
nevsk [136]
None of the above, nothing is there
7 0
3 years ago
Read 2 more answers
A concave lens has a focal length of 25cm. it's power in diaptor is​
IgorLugansk [536]

As we know that :

\begin{gathered}\large{\boxed{\sf{P \: = \: \dfrac{1}{f}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{1}{-25}}}\end{gathered}

Power, is in Meter. So divide focal length by 100

\begin{gathered}\rightarrow {\sf{P \: = \: \dfrac{1}{\dfrac{-25}{100}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{-100}{25}}} \\ \\ \rightarrow {\sf{P \: = \:- 4}} \\ \\ \underline{\sf{\therefore \: Power \: of \: Concave \: lens \: is \: - \: 4D}}\end{gathered}

8 0
2 years ago
If the outer conductor of a coaxial cable has radius 2.6 mm , what should be the radius of the inner conductor so that the induc
mel-nik [20]

Answer:

Inner radius = 2 mm

Explanation:

In a coaxial cable, series inductance per unit length is given by the formula;

L' = (µ/(2π))•ln(R/r)

Where R is outer radius and r is inner radius.

We are given;

L' = 50 nH/m = 50 × 10^(-9) H/m

R = 2.6mm = 2.6 × 10^(-3) m

Meanwhile µ is magnetic constant and has a value of µ = µ_o = 4π × 10^(−7) H/m

Plugging in the relevant values, we have;

50 × 10^(-9) = (4π × 10^(−7))/(2π)) × ln(2.6 × 10^(-3)/r)

Rearranging, we have;

(50 × 10^(-9))/(2 × 10^(−7)) = ln((2.6 × 10^(-3))/r)

0.25 = ln((2.6 × 10^(-3))/r)

So,

e^(0.25) = (2.6 × 10^(-3))/r)

1.284 = (2.6 × 10^(-3))/r)

Cross multiply to give;

r = (2.6 × 10^(-3))/1.284)

r = 0.002 m or 2 mm

5 0
4 years ago
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