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3 years ago

Which of the following statements is true about magnetic fields produced by current-carrying wires?

2 answers:

7 0

The larger the current flowing in a wire, the stronger the magnetic field
is that surrounds the wire.

That's why, if you want to make an electromagnet stronger, one way to
do it is to add another battery. By increasing the voltage, you'll increase
the current flowing in the coils of wire, and the electromagnet will be stronger.

kari74 [83]3 years ago

6 0

Answer:

option (a) and (C)

Explanation:

The magnetic field strength due to a current carrying wire is directly proportional to the amount of current flowing through the conductor and the length of the conductor. By the Biot Savart's law, the amount of magnetic field strength produced due to a small length element is given by

dB = k dl x i / r^2

Where, dl is the small length element, i be the current and r be the distance from the conductor where the magnetic field strength is to be calculated.

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Suppose that a ball is released from the window of a train that is moving with constant velocity. The path of the ball, as obse

barxatty [35]

True, the path of the ball, as observed from the train window, will be a horizontal straight line.

An object projected from a certain height has a parabolic path when observed from a fixed point.

However, if the reference point is moving at the same velocity as the object, the path of the object's motion appears to be a straight line.

When the ball is released from the window of the train, it will move at the same constant velocity as the train, and the path of the ball's motion observed from the train window will be a straight line.

Thus, we can conclude that the given statement is true. The path of the ball, as observed from the train window, will be a horizontal straight line.

Learn more about path of motion of objects here: brainly.com/question/82610

7 0

2 years ago

During the first 50 s a truck traveled at constant speed of 25 m/s. Find the distance that it is traveled.

Allushta [10]

Time=50s
speed=25m/s

Distance = speed×time
=25×50
=1250m

DISTANCE TRAVELLED IS =1250m

6 0

2 years ago

A three branch parallel circuit has resistors of 27 W, 56 W, and 15 W. What is the total resistance?

Mekhanik [1.2K]

Answer:8.2 Ω

Explanation:

I ASSUME you mean Ω (ohms) and not W(atts)

Re = 1/(1 / 27 + 1/56 + 1/15) = 8.2263329... ≈ 8.2 Ω

6 0

2 years ago

HELP ASAP!!! Some bands hate playing in school gyms because sound waves easily reflect off the walls and floor. What could you d

jonny [76]

Answer:

1.) Covering the ceiling and walls with soft perforated boards

2.) Hanging curtains round the hall

3.) Having more opening in the wall.

Explanation:

This is due to what we called Reverberation due to poor acoustic properties.

Reverberation can be reduced by;

1.) Covering the ceiling and walls with soft perforated boards

2.) Hanging curtains round the hall

3.) Having more opening in the wall.

4 0

2 years ago

The body falls in a free fall 11s.Calculate: a) from what height the body of the paddle) what path did it fall during the last s

JulsSmile [24]

Answer:

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

We will use second equation of motion to find the height:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

$h = (0\ m/s)(11\ s) + (\frac{1}{2})(9.8\ m/s^2)(11\ s)^2\\\\$

h = 593.50 m

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

$v_{10} = 0\ m/s + (9.81\ m/s^2)(10\ s)\\\\v_{10} = 98.1\ m/s$

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height covered during last second = h₁₁ = ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

$h_{11} = (98.1\ m/s)(1\ s) + (\frac{1}{2})(9.8\ m/s^2)(1\ s)^2\\\\$

h₁₁ = 103 m

Now, we use first equation of motion for complete motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

$v_{f} = 0\ m/s + (9.81\ m/s^2)(11\ s)$

vf = 107.91 m/s

8 0

3 years ago