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4 years ago

6

Which of the following statements is true about magnetic fields produced by current-carrying wires?

2 answers:

Anit [1.1K]4 years ago

7 0

<span>The larger the current flowing in a wire, the stronger the magnetic field
is that surrounds the wire.

That's why, if you want to make an electromagnet stronger, one way to
do it is to add another battery. By increasing the voltage, you'll increase
the current flowing in the coils of wire, and the electromagnet will be stronger.</span>

kari74 [83]4 years ago

6 0

Answer:

option (a) and (C)

Explanation:

The magnetic field strength due to a current carrying wire is directly proportional to the amount of current flowing through the conductor and the length of the conductor. By the Biot Savart's law, the amount of magnetic field strength produced due to a small length element is given by

dB = k dl x i / r^2

Where, dl is the small length element, i be the current and r be the distance from the conductor where the magnetic field strength is to be calculated.

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if you count 20 beetles in a garden measuring 5 square meters,the population density of the beetles is

jolli1 [7]

Population density = Number of beetles / Unit Square Area

= 20 beetles / 5m² = 4 beetles per m²

7 0

3 years ago

A 6.5 x 104 W engine exerts a constant force on of 5.5 x 103 N on a car, the resulting velocity is?

jek_recluse [69]

Answer:

12m/s

Explanation:

Given parameters:

Power = 6.5 x 10⁴W

Force = 5.5 x 10³N

Unknown:

The resulting velocity = ?

Solution:

The velocity of a body is related to force and power using the expression below;

Power = Force x velocity

Insert the parameters and solve for velocity

6.5 x 10⁴ = 5.5 x 10³ x velocity

velocity = $\frac{6.5 x 10^{4} }{5.5 x 10^{3} }$ = 12m/s

4 0

3 years ago

TIMED! URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!!

Diano4ka-milaya [45]

The answer is 27.03 I just multiplied the two numbers

3 0

3 years ago

Read 2 more answers

On April 13, 2029 (Friday the 13th!), the asteroid 99942 mi Apophis will pass within 18600 mi of the earth-about 1/13 the distan

Sergeu [11.5K]

Answer:

Explanation:

Volume of asteroid = 4/3 x π x 160³

= 17.15 x 10⁶

mass = volume x density

= 17.15 x 10⁶ x 2600

= 445.9 x 10⁸ kg

kinetic energy

= 1/2 x 445.9 x 10⁸ x( 12.6 )² x 10⁶

= 35.4 x 10¹⁷ J .

2 )

energy of 15 megaton

= 4.184 x 10¹⁵ x 15 J

= 62.76 x 10¹⁵ J

No of bombs required

= 35.4 x 10¹⁷ / 62.76 x 10¹⁵

= 56.4 Bombs .

4 0

3 years ago

A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

6 0

4 years ago