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lesantik [10]
2 years ago
15

A massless, hollow sphere of radius R is entirely filled with a fluid such that its density is p. This same hollow sphere is now

compressed so that its radius is R/2, and then it is entirely filled with the same fluid as before. As such, what is the density of the compressed sphere?
a. 8p
b. p/8
c. p/4
d. 4p
Physics
1 answer:
Vesnalui [34]2 years ago
7 0

Answer:

a. 8p

Explanation:

We are given that

Radius of hollow sphere , R1=R

Density of hollow sphere=\rho

After compress

Radius of hollow sphere, R2=R/2

We have to find density of the compressed sphere.

We know that

Density=\frac{mass}{volume}

Mass=Density\times volume=Constant

Therefore,\rho_1 V_1=\rho_2V_2

Volume of sphere=\frac{4}{3}\pi r^3

Using the formula

\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3

\rho R^3=\rho_2\times \frac{R^3}{8}

\rho_2=8\rho

Hence, the density of  the compressed sphere=8\rho

Option a is correct.

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Objective lenses are contained in a ____________ that can be turned to put a particular objective lens in place to be used.
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Jared is reading an article about the heavy rains that have fallen recently in his town. But he can’t separate the facts from th
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<span>FACTS:
|
|
It’s that time of year again when the days are wet and cool.
         The rainy season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
   and precipitation occur in the form of rain.
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</span>OPINIONS:
|
<span>|         It’s that time of year again when the days are wet and cool.
The rainy season is the best season.
         Rain makes up part of Earth’s water cycle.
         Water evaporates from streams, lakes, and oceans, then condensation
            and precipitation occur in the form of rain.
Precipitation in the form of rain is better than snow.
Snow this time of year makes people gloomy.
         Rain is a great boon to local farmers.
         It helps their crops grow.</span>

6 0
3 years ago
Read 2 more answers
Light of wavelength 425.0 nm in air falls at normal incidence on an oil film that is 850.0 nm thick. The oil is floating on a wa
creativ13 [48]

Answer:

in oil film        λ = 303.57 10⁻⁹ m

in the water film    λ = 319.55 10⁻⁹ m

Explanation:

When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,

when light reaches a surface it has a mass much greater than the mass of the photons (m = 0), therefore there is an elastic collision where the frequency does not change, due to the speed of light in the material medium changes, therefore the only possibility is that the wavelength in the material changes, to maintain the relationship

             v = λ f

in the void we have

             c = λ₀ f

we divide the two expression

            c / v = λ₀ / λ

the refractive index is

             

              n = c / v

              n = λ₀ /λ

              λ = λ₀ / n

let's calculate

in oil film

            λ = 425 10⁻⁹ / 1.40

            λ = 303.57 10⁻⁹ m

in the water film

            λ = 425 10⁻⁹ / 1.33

            λ = 319.55 10⁻⁹

those wavelengths are in the ultraviolet

3 0
2 years ago
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