The wavelength of the first order bright band light light is 714 nm .
Explanation:
We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.
The formula is
nλ =d sinθ
where, n is the order of maximum
λ is the wavelength of light
d is the distance between the lines on diffraction grating.
θ is the angle.
For the given equation n is 1 because the problem states that the light forms 1st order bright band
λ is unknown.
d = 
or 0.0000014 m
sin (30) = 0.5
so,
1(λ) = (0.0000014)(0.5)
= 0.0000000714
= 714 nm
Thus, The wavelength of the first order bright band light light is 714 nm .
Answer:
We can use optical fibers.
Explanation:
The optical fibers are the optical devices which is based on the total internal reflection.
The optical fiber has two layers, one is called core and the other is called cladding.
The refractive index of core is more than the cladding.
As a ray of light falls on the core at more than the critical angle for that pair of media(core and cladding), it suffers the total internal reflection at the interface.
For the answer to the question above,
<span>There is nothing in the equations to suggest that the string moves in the x direction so D) v_x(x,t)=0.
</span>
y(x,t) = A sin(kx-omega t)
d{y(x,t)}/d{x} = A k cos(kx - omega t)
Kinetic energy<span> increases with the square of the velocity (KE=1/2*m*v^2). If the velocity is doubled, the KE quadruples. Therefore, the </span>stopping distance<span> should increase by a factor of four, assuming that the driver is </span>can<span> apply the brakes with sufficient precision to almost lock the brakes.</span>
Taking right movement to be positive means leftward movement is negative.
Hence we have a deceleration of
Using this 'suvat' equation
we can determine the initial velocity
Hence the initial velocity is 13.0 meters per seconds
