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Korolek [52]
3 years ago
7

Jake sold 36 tickets to the school fair and jeanne sold 15 what is the ratio

Mathematics
1 answer:
artcher [175]3 years ago
3 0
12:5 is what you are looking for. 12/5 in fraction form
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using figures below, identify the corresponding parts of each of the triangles. then write a similarity statement that includes
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4 0
3 years ago
Aziza has a triangle with two sides measuring 11 in. and 15 in. She claims that the third side can be any length as long as it i
bixtya [17]
We determine the third side of a triangle if we are given certain measurements or parameters like two sides and an angle, two angles and one side or two sides and the type of triangle. For this case, we are only given the measurement of the two sides of the triangle. In order to solve the third side, we assume that the triangle is a right triangle where one angle is a right angle. From this assumption, we use the Pythagorean Theorem:
 c^2 = a^2 + b^2 where c is the hypotenuse, a and b are the remaining sides of the triangle

From this assumption, we can already calculate the third side by either assuming that 15 in. is the hypotenuse or to assume the two to be the shorter sides of the triangle. By assuming 15 in. to be the hypotenuse, we obtain a measurement of the third side a value of 10.20 in. while assuming the latter we obtain a value of 18.60 in. From the claim of Aziza, she is correct when she said that the third side is greater than 4 in. however she is wrong in claiming that the third side can have any length since a triangle has always its corresponding parameters depending on what type it is or the measurements being given in the problem. For this case, the third side can be 18.60 in. or 10.20 in.
4 0
3 years ago
Read 2 more answers
Car dealerships claim to make most of their money from servicing cars. In a certain month, an Acura dealership sold fifteen less
MA_775_DIABLO [31]

Answer:

New cars sold = 20,

Used cars sold = 25

Cars serviced = 290

Step-by-step explanation:

In a month they sold fifteen less used cars than twice the number of new cars.

Lets say 'x' number of new cars were sold, then:

The number of used car sold is:

2\times x-15=2x-15

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

12\times x+50=12x+50

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

x+(2x-15)+(12x+15)=335

Solving for 'x' we get:

x+2x+12x-15+50=335

15x+35=335

15x=335-35=300

x=\frac{300}{15}=20

Therefore, the number of new cars sold in that month is 20.

Number of used car sold =2x-15=2\times 20-15=40-15=25

Number of cars serviced =12\times x+50=12\times20+50=240+50=290

We can also cross check by summing them up:

290+25+20=335

8 0
3 years ago
10. Subtract the<br>fractions.<br>20 1 / 2 - 15 1/2 =<br>*Bonus: Reduce the<br>fraction.​
BartSMP [9]

Answer: 5

Step-by-step explanation:

20\frac{1}{2}-15\frac{1}{2}

20-15(\frac{1}{2}-\frac{1}{2})

5

3 0
4 years ago
Please help me on this!
Elena-2011 [213]
For when x is 4 g will be 80 and f will be 108 for when x is 5, g will be 160 and x will be 110 so option 1 as 160-110 is 50

Hope it helped
8 0
2 years ago
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