All categories

3 years ago

What is the result of adding -3x2 - 5x + 1 and 8x2 - 2x - 9

Mathematics

1 answer:

Fudgin [204]3 years ago

6 0

(-3x^2 - 5x + 1) + (8x^2 - 2x - 9)

1st remove the parenthesis

-3x^2 - 5x + 1 + 8x^2 - 2x - 9

then combine like terms

5x^2 - 7x - 8 is the final answer

You might be interested in

Kim's weekly pay is two thirds of Alicia's.Together they earn $600 per week

garik1379 [7]

A + k = 600
k = 2/3a

a + 2/3a = 600
3/3a + 2/3a = 600
5/3a = 600
a = 600 * 3/5
a = 1800/5
a = 360

k = 2/3a
k = 2/3(360)
k = 720/3
k = 240

so Kim's pay is $ 240 and Alicia's pay is $ 360

7 0

3 years ago

A doormat is 3 feet by 2 feet.

Papessa [141]

Area is equal to the length times the width. by multiplying 2 by 3 you should find the area is 6 ft^2

8 0

3 years ago

Help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Ugo [173]

Answer:

10400

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).

koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

$sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}$

Therefore,

$\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...$

hence the first four nonzero terms of the series are

$\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12$

6 0

3 years ago

Sam Monte deposits $21,500 into Legal Bank, which pays 6% interest that is compounded semiannually. Using the table in the handb

tatuchka [14]

2,149,999.99 I dont know if it's right but this is what I got haha

6 0

4 years ago