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Daniel [21]
3 years ago
10

Which function in the vertex form is equivalent to f(x)=x^2+6x+3

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

B. f(x) = (x + 3)2 − 6


Step-by-step explanation:


Sati [7]3 years ago
5 0

Answer:

f(x)=(x+3)^2-6

Step-by-step explanation:

We have been given a function f(x)=x^2+6x+3. We are asked to find the function equivalent to our given function in vertex form.

To convert our given function in vertex form, we need to complete the square for our given function as:

Add and subtract (\frac{b}{2})^2 from equation:

(\frac{b}{2})^2=(\frac{6}{2})^=3^2=9

f(x)=(x^2+6x+9)+3-9

f(x)=(x^2+2\cdot 3x+3^2)-6

f(x)=(x+3)^2-6

Therefore, the f(x)=(x+3)^2-6 is equivalent to our given function in vertex form.

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The diameter of a circle has endpoints P(-12, -4) and Q(6, 12).
nexus9112 [7]

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Answer:

  (x +3)² +(y -4)² = 145

Step-by-step explanation:

The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...

  A = (P +Q)/2

  A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2

  A = (-3, 4)

The equation of the circle for some radius r is ...

  (x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle

The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...

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  r² = 81 +64 = 145

Then the equation of the circle is ...

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3 0
3 years ago
"The product of two numbers is 169. If the L.C.M. of these numbers is 13, find their H.C.F. "
umka21 [38]

Answer:

13

Step-by-step explanation:

HCF = Product of two numbers ÷  LCM of these numbers

HCF = \frac{169}{13}

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Therefore, the repeated root of this quadratic is the solution to 5x - 3=0, which is 3/5

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