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Daniel [21]
3 years ago
10

Which function in the vertex form is equivalent to f(x)=x^2+6x+3

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

B. f(x) = (x + 3)2 − 6


Step-by-step explanation:


Sati [7]3 years ago
5 0

Answer:

f(x)=(x+3)^2-6

Step-by-step explanation:

We have been given a function f(x)=x^2+6x+3. We are asked to find the function equivalent to our given function in vertex form.

To convert our given function in vertex form, we need to complete the square for our given function as:

Add and subtract (\frac{b}{2})^2 from equation:

(\frac{b}{2})^2=(\frac{6}{2})^=3^2=9

f(x)=(x^2+6x+9)+3-9

f(x)=(x^2+2\cdot 3x+3^2)-6

f(x)=(x+3)^2-6

Therefore, the f(x)=(x+3)^2-6 is equivalent to our given function in vertex form.

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The quotient of 4 and 1/5 will be greater than 4.
bixtya [17]
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8 0
3 years ago
Read 2 more answers
This one is algebra.....
vodomira [7]

{Hello~!\:}

<h2>Your answer will be is :</h2><h2></h2><h3>B. And C.</h3><h3></h3>

Hope It Helps. . .

#LearnWithBrainly

\underline{A~n~s~w~e~r~:\;}

\bold{Jace\;} ^-^

7 0
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I neep helpppppppppp
skelet666 [1.2K]

Answer:

D

Step-by-step explanation:

x  = 5 - 2y \\ y = 3(5 - 2y) - 8 \\ y = 15 - 6y - 8 \\ y = 7 - 6y \\ 7y = 7 \\ y = 1

x = 5 - 2y \\ x = 5 - 2 = 3 \\

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