Question

Uche pumps gasoline at a rate of 18 L/min What is Uche's pumping rate in mL/s ?

Answer 1

There are 1000 mL in a Liter  and 60 seconds in a minute

18 L / min = 18,000 mL /min

so in mL/s the answer is  18000 / 60  =  300 mL/s  Answer

Answer 2

Answer:

$\frac{300\text{ ml}}{\text{ second}}$

Step-by-step explanation:

We have been  given that Uche pumps gasoline at a rate of 18 L/min. We are asked to find Uche's pumping rate in mL/s.

To solve our given problem we need to convert our given rates.

1 liter = 1000 ml

1 minute = 60 seconds.

Upon

$\text{Uche's pumping rate}=\frac{\text{18 L}}{\text{min}}\times \frac{\text{1000 ml}}{\text{L}}\times \frac{\text{1 min}}{\text{60 seconds}}$

$\text{Uche's pumping rate}=\frac{18\times\text{1000 ml}}{\text{60 seconds}}$

$\text{Uche's pumping rate}=\frac{18,000\text{ ml}}{\text{60 seconds}}$

$\text{Uche's pumping rate}=\frac{300\text{ ml}}{\text{ second}}$

Therefore, Uche's pumping rate in mL/s would be $\frac{300\text{ ml}}{\text{ second}}$.