Answer:
7
Step-by-step explanation:
The average rate of change of f(x) in the close interval [ a, b ] is

Here [ a, b ] = [2, 5 ]
f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15
f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus
average rate of change =
=
= 7
Answer:
37.5 cm
Step-by-step explanation:
See attached for reference.
let the diagonal be x,
By Pythagorean formula:
x² = (22.5)² + (30)²
x = √[(22.5)² + (30)²]
x = 37.5 cm
Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x
we need to find the minimum value of z
z' = 2x + 154 which = zero for minm or maxm value
x = -77 and y = 154 -77 = 77
so the 2 numbers are -77 and 77
Answer:
A
Step-by-step explanation:
B is the answer hope this helps :)