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sineoko [7]
3 years ago
14

PLEASE HELP 20 POINTS + BRAINLIEST IF ANSWERED Which method correctly solves the equation using the distributive property? Negat

ive 0.2 (x minus 4) = negative 1.7 Negative 0.2 (x minus 4) = negative 1.7. Negative 0.2 x minus 4 = negative 1.7. Negative 0.2 x = 2.3. x = negative 11.5. Negative 0.2 (x minus 4) = negative 1.7. x minus 4 = 0.34. x = 4.34. Negative 0.2 (x minus 4) = negative 1.7. Negative 0.2 x + 0.8 = negative 1.7. Negative 0.2 x = negative 2.5. x = 12.5. Negative 0.2 (x minus 4) = negative 1.7. Negative 0.2 x minus 0.8 = negative 1.7. Negative 0.2 x = negative 0.9. x = 4.5.
Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

Negative 0.2 (x minus 4) = negative 1.7

Step-by-step explanation:

Blababa [14]3 years ago
3 0

Answer:

Negative 0.2 (x minus 4) = negative 1.7

Step-by-step explanation:

took the test;)

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3 years ago
Write the standard form of the quadratic equation modeled by the points shown in the table below.
rjkz [21]

Answer:

y = 2x² - 5x + 7

Step-by-step explanation:

General form of a quadratic is:

y = Ax² + Bx + C

Using the given points, construct equations and solve for A,B and C.

When x = 0, y = 7

7 = A(0)² + B(0) + C

C = 7

y = Ax² + Bx + 7

When x = -1, y = 14

14 = A(-1)² + B(-1) + 7

A - B = 7

A = 7 + B

When x = 1, y = 4

4 = A(1)² + B(1) + 7

A + B = -3

(7 + B) + B = -3

2B = -10

B = -5

A = 7 + (-5)

A = 2

y = 2x² - 5x + 7

5 0
3 years ago
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neonofarm [45]

1. M

2. F

3. J

4. D

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5 0
3 years ago
The lifetime, in years, of some electronic component is a continuous random variable with the density f(x) =   k x4 for x ≥ 1
yuradex [85]

I suppose the density is supposed to be

f(x)=\begin{cases}\frac k{x^4}&\text{for }x\ge1\\0&\text{otherwise}\end{cases}

(since kx^4 diverges as x\to\infty, and 0 is conveniently left out of the domain)

For this to be a proper density function, it must be positive (it is) and its integral over the support [1,\infty) must evaluate to 1. We have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_1^\infty\frac k{x^4}\,\mathrm dx=-\frac k{3x^3}\bigg|_1^\infty=\frac k3=1

which means k=3.

The distribution function is obtained by integrating the density:

F(x)=\displaystyle\int_{-\infty}^xf(t)\,\mathrm dt=\begin{cases}0&\text{for }x

The probability that the component exceeds 2 years in its lifetime is

P(X>2)=1-P(X\le 2)=1-F(2)=1-\left(1-\dfrac18\right)=\dfrac18

3 0
3 years ago
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