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Mashcka [7]
2 years ago
13

PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORRECT. (no links my comput

er is slow and no ctrl c ctrol v if possible
Given a right triangle with leg lengths f and g, and hypotenuse h, if f = 7 cm and h = 11.2 cm, what is g?

Show your work.
Mathematics
1 answer:
motikmotik2 years ago
8 0

Step-by-step explanation:

o2+a2=h2

100} h^{2}=(10ft)^{2} +(17ft)^{2}

h2=100ft2+289ft2

h=389ft2−−−−−√

→19.7ft

this is an example on how to do it

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Select the correct answer from the drop-down menu.<br> Fill in the missing number in the equation.
noname [10]

Answer:

8

Step-by-step explanation:

a A + b A where A is a matrix and a and b are scalars

( a+b) A

3+5 \left[\begin{array}{cc}-1&2\\4&-5\end{array}\right] = 8\left[\begin{array}{cc}-1&2\\4&-5\end{array}\right]

         

7 0
3 years ago
What is the quotient (2x^2+10x+12)/(x+3)
vova2212 [387]

Answer:

3

Step-by-step explanation:

4 0
2 years ago
Please help me im really bad only higher grades can answer
myrzilka [38]
Positive sorry if it’s wrong good luck
3 0
2 years ago
Read 2 more answers
Angela is following this recipe to make biscuits.
maks197457 [2]

Answer : The amount of margarine needed is 1 kg.

Step-by-step explanation :

First we have to convert volume of syrup from mL to L.

Conversion used:

1 L = 1000 mL

or, 1 mL = 0.001 L

So, 225 mL = 0.225 L

Now we have to calculate the amount of margarine needed.

As, 0.225 L of syrup needed 150 g of margarine

So, 1.8 L of syrup needed \frac{1.5L}{0.225L}\times 150 g=1000g of margarine

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Therefore, the amount of margarine needed is 1 kg.

4 0
3 years ago
Y is directly proportional to x when y=30, x=6
rosijanka [135]

Answer:

a) y = 5x

b) y = 60

Step-by-step explanation:

Since, y is directly proportional to x when y=30, x=6

\therefore \:  y \:  \alpha \:  \: x \\ \therefore \:  y =  kx ...(1) \\ plug \: y = 30 \: and \: x = 6  \: in \: eq \: (1)\\ 30 = k \times 6 \\ k =  \frac{30}{6}  \\ k = 5 \\ plug \: k = 5 \: in \: (1) \\ y = 5x....(2) \: (required \: equation) \\ plug \: x = 12 \: in \: eq \: (2) \\ y = 5 \times 12 \\  \huge \red{ \boxed{y = 60}}

4 0
2 years ago
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