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3 years ago

Factor X^3-7x^2-5x+35 by grouping. What is the resulting expression

Mathematics

2 answers:

WARRIOR [948]3 years ago

5 0

Answer:

(x-7) (x^2-5)

Step-by-step explanation:

x^3-7x^2-5x+35

Factor out an x^2 from the first two terms and -5 from the last 2 terms

x^2 (x-7) -5(x-7)

Factor out (x-7)

(x-7) (x^2-5)

-BARSIC- [3]3 years ago

3 0

Answer:

(x - 7) (x^2 - 5)

Step-by-step explanation:

Factor the following:

x^3 - 7 x^2 - 5 x + 35

Factor terms by grouping. x^3 - 7 x^2 - 5 x + 35 = (x^3 - 7 x^2) + (35 - 5 x) = x^2 (x - 7) - 5 (x - 7):

x^2 (x - 7) - 5 (x - 7)

Factor x - 7 from x^2 (x - 7) - 5 (x - 7):

Answer: (x - 7) (x^2 - 5)

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2 years ago

Write a number with two decimals places that is bigger than 4 1/5 but smaller then 4.25 (Could u explain so i can actually under

zubka84 [21]

The possible answers are:
4.21
4.22
4.23
4.24

Explanation:
We want a number between 4 1/5 and 4.25. We will convert 4 1/5 to a decimal first:

Divide 1 by 5: 1/5 = 0.2.

This makes 4 1/5 = 4 + 1/5 = 4 + 0.2 = 4.2.

We want a number between 4.2, which can be written as 4.20, and 4.25. Any number between will do, so the possible answers would be
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7 0

3 years ago

Read 2 more answers

How do I solve -8=-(x+4)

DiKsa [7]

First do distrubutive property
-(x+4)=-8
Multiply the parenthesis by the invisible -1 in the front
: -x-4=-8
Now add 4 to both sides
-x=-4
then divide -1 by both sides
x=4 is your answer

8 0

3 years ago

Read 2 more answers

Find the first term and the common ratio third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$