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3 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics

1 answer:

vova2212 [387]3 years ago

3 0

⭐Hola User_____________

⭐Here is Your Answer..!!

______________________

↪COMPLEX NUMBERS

↪usually in the complex form , the real numbers gets added to real number and the imaginary number gets added to the imaginary number

↪thus

↪(a+ib) + ( x+iy)= ( a+x) + i (b+y)

↪thus here

↪(-5+2i) + ( 3-6i)

=》 ( -5 + 3) + i ( 2-6)

=》 -2 +i (-4)

=》 -2 -4i

↪thus the answer is -2-4i

________________________

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Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

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