cos4x = cos2x
We know that:
cos2x = 1-2cos^2 x
==> cos4x = 1-2cos^2 (2x)
Now substitute:
==> 1-2cos^2 (2x) = cos2x
==> 2cos^2 (2x) + cos2x - 1 = 0
Now factor:
==> (2cos2x -1)(cos2x + 1) = 0
==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3
==> x1= pi/6 , 7pi/6
==> x1= pi/6 + 2npi
==> x2= 7pi/6 + 2npi
==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.
<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>
-16, +2 are two nhmbers that multiply to -32 and add to -14
What is the square root of 36x^4?
√36x^4 =
6x²
(√36=6 and √x^4 = x²)
Answer:
I explain down below:
Step-by-step explanation:
First, you divide the combined rectangle into separate parts. Then you find the area of the first rectangle. Then the second and/or third one.
After all the areas have been solved, you add all of the areas together.
Hope this helps!
