Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
The correct equation is 8.7 + b = 54.6
Step-by-step explanation:
because it is given that measure of side a is 8.7cm, in all other equations the values of a is different.
Answer:
About 42%
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
You can eliminate answer A because when X=1, Y must equal 33.75 not 33.
You can eliminate answer B because when X=0, Y must equal 0 not 1.
You can eliminate answer D because this answer has the X and Y coordinates reversed. When X=1, Y= 33.75. When X=4, Y=135, etc.
<em>24p² + pq - 23q² = </em>
<em>= 24p² + 24pq - 23pq - 23q²</em>
<em>= 24p(p + q) - 23q(p + q)</em>
<em>= (p + q)(24p - 23q)</em>
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