Answer:
Two possible solutions
Step-by-step explanation:
we know that
Applying the law of sines

we have



step 1
Find the measure of angle A

substitute the values


The measure of angle A could have two measures
the first measure------->
the second measure ----->
step 2
Find the first measure of angle C
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 3
Find the first length of side c

substitute the values


therefore
the measures for the first solution of the triangle are
, 
, 
, 
step 4
Find the second measure of angle C with the second measure of angle A
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 5
Find the second length of side c

substitute the values


therefore
the measures for the second solution of the triangle are
, 
, 
, 
Okay so the area of a rectangle x by y with a border of width b will be:
A=(x+2b)(y+2b)
A=xy+2bx+2by+4b^2 we are told that A=320, x=11, and y=15 so now we have:
320=165+22x+30x+4x^2, now I am using x as the border width...
4x^2+55x+165=320 is the equation that they listed..
...
4x^2+55x-155=0 using the quadratic formula for efficiency...
x=(-55±√5505)/8 since x>0
x≈2.399 which for some unknown (incorrect) reason they rounded to
x=2.5
So in short, your answer is a)
The equation given has a slope of -3. See it? The equation we are looking for must have the same slope because the lines are parallel to each other. This means the lines never meet or touch on the xy-plane.
We use the point-slope formula to find the equation.
Here is the point-slope formula:
y - y_1 = m(x - x_1)
y - 4 = -3(x - (-3))
y - 4 = -3(x + 3)
y - 4 = -3x - 9
We now isolate y to find our equation.
y = -3x - 9 + 5
y = -3x - 4
Done.
Answer:
6=8
Step-by-step explanation:
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