There's 10 letters in volleyball. 4 of them are l's. So 4/10.
Fraction: 4/10
Decimal: 0.4
Percent: 40%
Hope this helps! :)
Answer:
X = 6 , – 2
Step-by-step explanation:
| 4x +4| - 10 =3x
4x +4 - 10 = 3x
4x - 3x = 10 - 4
x = 6
_____o___o____
– (4x + 4) – 10 = 3x
– 4x – 4 – 10 = 3x
3x + 4x = – 4 – 10
7x = – 14
x = – 14/ 7
x = – 2
I hope I helped you^_^
Answer:
a.No
b.No
c.No
Step-by-step explanation:
a.No,Such set does not exist .A set of natural numbers is N
Every point of this set is an isolated point but no accumulation point
Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set
Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself
Interior point of set :Let 
.Then a is called interior point of set when its neighborhood is a subset of set S.
When a set is uncountable then interior point exist it is necessary for interior points existance .
Boundary points :Let .If every non empty neighborhood of a intersect S and complement of S.
Every member of a set is a boundary point
b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers
c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point
Common Examples of Irrational Numbers
Pi, which begins with 3.14, is one of the most common irrational numbers. ...
e, also known as Euler's number, is another common irrational number. ...
The Square Root of 2, written as √2, is also an irrational number.
You can see how this works by thinking through what's going on.
In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97
What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.
So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.
So the population after x years is 1200 * 0.97x
